Make y the subject of the formula.

$T=2\pi\sqrt\frac{x^2\ +\ y^2}{gx}$

Answers

$T=2\pi\sqrt\frac{x^2\ +\ y^2}{gx}$

$\frac{T^2}{4\pi^2}=\frac{x^2y^2}{gx}$

$T^2gx=4\pi^2(x^2+y^2)$

$T^2gx=4\pi^2x^2 + 4\pi^2y^2$

$y^2=\frac{T^2gx-4\pi^2x^2}{4\pi^2}$

$y=\pm\sqrt\frac{T^2gx-4\pi^2x^2}{4\pi^2}$

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raphael answered the question on December 17, 2016 at 07:44

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