Make x the subject of in the following expression

      

$\frac{x^4 - 4}{x^2 -2} \ = K$

  

Answers


Raphael
$\frac{(x^2)2 - 4}{x^2 - 2} \ = K$

$\frac{(x^2 -2)(x + 2)}{x^2 - 2} \ = K$

x=$x^2 + 2 \ = K$

$\pm \sqrt{K - 2}$
raphael answered the question on January 16, 2017 at 12:38


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