Get premium membership and access questions with answers, video lessons as well as revision papers.

Figure 4 shows a uniform metre rule of weight I N with two weights of 0.18 N and 0.12 N suspended from its ends.

      

Figure 4 shows a uniform metre rule of weight I N with two weights of 0.18 N and 0.12 N suspended from its ends.
balance4182017319.jpg
Determine how far from the 0.18 N weight a pivot should be placed in order to balance the meter rule

  

Answers


John
Let the pivot be at point X, x cm from the 50 cm mark on the left hand side,

clockwise moment = Anticlockwise moment

(x x 1) + 0.12 (50 + x) = (50 - x)0.18

x = 2.307 cm, Answer = 50 cm - 2.307 cm = 47.69 cm (4 s.f)
johnmulu answered the question on April 18, 2017 at 12:25


Next: Figure 9 shows a uniform light bar one meter in length in equilibrium under the action of forces F1, F2, F3 and F4. All the forces are in the same plane. Use the information on the figure to answer questions a) and b)
Previous: Figure 9 shows a uniform bar in equilibrium under the action of two forces.

View More Physics Questions and Answers | Return to Questions Index


Learn High School English on YouTube

Related Questions