The spiral spring shown in Figure 4 are identical. Each spring has a spring constant k = 300 N/m

      

The spiral spring shown in Figure 4 are identical. Each spring has a spring constant k = 300 N/m
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Determine the total extension caused by the 90 N weight. (Ignore the weight of the springs and connecting rods)

  

Answers


John
F = ke, spring constant of the three springs in series = 3 x 300 = 900N/m

extension = $\frac{90}{900}$ = 0.1 m

Spring constant of the two springs in series = 2 x 300 = 600N/m,

extension = $\frac{90}{600}$ = 0.15 m

Total extension = 0.15 + 0.10 = 0.25
johnmulu answered the question on April 19, 2017 at 08:57


Next: Two identical spring balances R and S each weighing 0.5 N are arranged as shown in Figure 2.
Previous: The graph in Fig. 7 represent the relations between extension, e and mass, m added on two springs x and y.

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