Parallel = F = 2ke1 40 = 2ke = e = $\frac{20}{k}$
Single = F = 2ke = 20 = ke = e2 = $\frac{20}{k}$
$e_T =e_1 + e_2 \; =\; \frac{20}{k}+\frac{20}{k}=\; \frac{40}{k} = $ K = 2N/cm
Extension of each spring = 10, k = $\frac{20N}{10cm}$ = 2N/ cm
johnmulu answered the question on April 19, 2017 at 09:24
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