i) Nitrogen (II) Oxide (NO)
ii) 4NH$4NH_{3(g)}+ 3CUO \rightarrow 2N_{2(g)} + 3H_2O_{(l)} + 3Cu$
Oxidation number of reducing agent increases hence ammonia is the reducing agent
Oxidation number of reducing agent increases hence ammonia is the reducing agent
Oxidation number of copper (Cu) decreases from + 2 to O hence an oxidizing agent
iii) NH$_4NO_{3(s)} \rightarrow N_2O_{(g)} + 2H_2O_{(g)}$
johnmulu answered the question on April 20, 2017 at 07:07
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