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perimeter of the triangle,P=40cm
Hypotenuse, c=17cm
other sides, b+h=40-17
b+h=23..............(1)
using pythagoras theorem,
b^2 + h^2 = 23^2..........(2)
from eqn (1), b=23-h
subtituting equation b in eqn (2)
(23-h)^2 + h^2 = 17^2
23(23-h)-h(23-h) + h^2 = 289
529-46h+2h^2 = 289
240-46h+2h^2=0
120-23h+h^2=0....................(3)
Solving equation (3) quadratically,
value of h=15
thus 15+b=23
b=8
Therefore the sides are 15cm and 8cm.
Teacher Robin answered the question on February 19, 2018 at 11:41
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