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XC03=XO+CO2
mass of XCO3=3.1
mass of XO =2.0
mass of CO2 =1.1
moles of C02 produced=1.1/44
=0.025moles
Sinse the mole ratio of the reaction is 1:1,moles of XO produced is 0.025.
XO will be reduced as,
X0 + H2 = X + H20
mole ratio of reaction is 1:1
therefore, the moles of X produced is 0.025
RAM of X= mass/ moles
=1.6/0.025
=64
Therefore the atomic number is 32.
Mr Masinde answered the question on May 5, 2018 at 08:37
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