a) the speed of the sound in air
Speed v=(2*500)m/3s =333.3m/s.
b) the distance between the cliffs
Let the distance between the student and the other cliff be x.
Then, 2x/(3+2)=333.3
x=(333.3*5)/2 =833.25m
Therefore, the distance between the two cliffs is= (500+833.25)= 1333.25m
Moraa orina answered the question on April 8, 2018 at 10:05
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