From Q = Q0 v{(1 + (1/VwSo).dy/dt}
dy/dt = 10 cm/h
= 10/(60 x 60) = 2.778 x 10-3 cm/s
S0 = 3 x 10-4; Vw = 2.5 cm/s; Q0 = 150 m3/s
Thus,
Q = 150 v(1 + [1/(2.5 x 3 x 10-4) x 2.778 x 10-3])
= 150 v(1+3.704) = 150 x 2.1689 = 325 m3/s
jim items answered the question on April 9, 2018 at 18:26
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