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Heat lost by tray = mc?? = 0.4*900*(20-0)= 7200J
Heat lost by water = mc??= 0.3*4200*20 = 25, 200J
Latent heat of ice given out = mlf = (0.3-0.06)*340, 000 = 999, 600J
Total heat energy absorbed by the refrigerator =3600+25200+999600= 114000J
Hence amount of heat removed per minute = 114000J/80min = 1425J/min
Moraa orina answered the question on April 10, 2018 at 18:02
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