i) The angle of refraction in water.
4/3= sin 600/sin r
r=sin-1(3sin600/4)= 40.50
ii) The angle of incidence at the oil-glass interface.
o?g=sin q/sin r
By the principle of reversibility of light, a?g=sin 600/sin r = 3/2
r= sin-1(2sin 600/3) =38.270.
Also, o?g= o?a* a?g=5/4
Therefore, 5/4= sin q/sin 38.270
q=sin-1(5sin38.270/4)=48.40
Moraa orina answered the question on April 10, 2018 at 18:18
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