a) The speed, v
Tmin= mv2/r –mg
3=0.4(v2/1 -10)
V2=(3+4)/0.4 =70/4
V=(70/4)1/2=4.183m/s
b) Maximum tension in the string
Tmax=m(v2/r +g) =0.4(70/4 +10)
= 11N
c) The tension when the string is just horizontal
T=mv2/r = 0.4*70/4 =7N
Moraa orina answered the question on April 11, 2018 at 17:06
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