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a) The coefficient of friction, µ
FR=FC=mv2/r = µR=µmg
Therefore v2/r =µg
µ = 202/100*10 =0.4
b) The angle at which the road should be banked to enable the motorist negotiate the corner at a critical
speed of 20m/s.
tanO= v2/rg =0.4
O=tan-10.4 =21.80
Moraa orina answered the question on April 11, 2018 at 17:16
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