a) The power supplied to the transformer.
Efficiency=(power output/ power input)x100
80=[(60x10)/power input]x100
Power input= (60x10x100)/80
=750W
b) The current in the primary coil
Power input=VPxIP
IP=750W/240V =3.125A
Moraa orina answered the question on April 11, 2018 at 17:35
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