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Energy of the radiation=hf=[6.63x10-9x4.3x1014]/ [1.602x10-19J]= 1.7796eV
Since the energy of the radiation is less than the workfunction, no photoelectric emission will occur.
Alternatively;
Workfunction=hf0=2.6x1.602x10-19
f0=[2.6x1.602x10-19]/[6.63x10-9]= 6.74x1014Hz
Since the frequency of the radiation is less than the threshold frequency of the metal, there is no
photoelectric emission.
Moraa orina answered the question on April 12, 2018 at 06:51
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