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Figure 7 shows a mass of 30 kg being pulled from point P to point Q, with a force of 200 N parallel

      

Figure 7 shows a mass of 30 kg being pulled from point P to point Q, with a force of 200 N parallel to an inclined plane. The distance between P and Q is 22.5 m. In being moved from P and Q the mass is raised through a vertical height of 7.5 m.
physics51620171112.jpgDetermine the work done:
(I) By the force;
(II) On the mass;
(III) To overcome friction.

  

Answers


John
(I) work done by force = Fd = 200 x 22.5 = 4500 J

(II) Work done by mass = mgh = 30 x 10 x 7.5 = 2250 J

(III) Work done to friction = work done by force - work done on mass

= 4500 - 2250 = 2250 J
johnmulu answered the question on May 16, 2017 at 08:16


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