The cell in Figure 10 has an e.m.f of 2.1 V and negligible internal resistance.

      

The cell in Figure 10 has an e.m.f of 2.1 V and negligible internal resistance.
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Determine the
(i) Total resistance in the circuit
(ii) Current in the circuit
(iii) Reading of the voltmeter

  

Answers


John
(i) Parallel circuit: $\frac{1}{R} = \frac{1}{20}+ \frac{1}{30} = \frac{1}{12}$ = R = 12

Total resistance = 10 + 12 = 22 ohms

(ii) I = $\frac{V}{R} = \frac{2.1}{22} = 0.095 A$

(iii) V = IR

10 x 0.095 = 0.95 V
johnmulu answered the question on May 23, 2017 at 10:49


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