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(i) I = $\frac{V}{R}$ = $\frac{1.5}{10}$ = 0.15 A
(ii) Voltage across the bulb = 1.5 V
R = $\frac{V}{I}=$\frac{1.5}{0.1}$ = 15 ohms
johnmulu answered the question on May 23, 2017 at 13:43
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