Comments in Computer Programming are used for the following reasons:
1.They is a point of communication between different programmers
2.They assist another programmer when correcting errors in a program
3.Makes the program understandable since it communicates what the source code is doing at various points
4.Make the program neat and structured
STEPHKIMOTHO answered the question on May 26, 2018 at 08:13
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Date posted: May 26, 2018. Answers (1)
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Date posted: May 13, 2018. Answers (1)
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- Given this class fragment,
class samp {
double *p;
public:
samp (do d) {
p = (double *) malloc(sizeof(double));
if (!p) exit (1); //allocation error
*p = d;
}
~samp() {free(p) ;}
//...
}; ...(Solved)
Given this class fragment,
class samp {
double *p;
public:
samp (do d) {
p = (double *) malloc(sizeof(double));
if (!p) exit (1); //allocation error
*p = d;
}
~samp() {free(p) ;}
//...
};
//...
samp ob1(1, ob2(0.0);
//...
ob2 = ob1;
what problem is caused by the assignment of ob1 to ob2?
Date posted: May 12, 2018. Answers (1)
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Constructing who #X
where x is the identifying character associated with each object when an object is destroyed, have a message similar to this displayed:
Destroying who #x
where, again, x is the identifying character. Finally, create a function called make_who() that returns a who object. Give each object a unique name.Note the output displayed by the program.
Date posted: May 12, 2018. Answers (1)
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other than the incorrect freeing of dynamically allocated memory, think of a situation in which it would be improper to return an object from a function.
Date posted: May 12, 2018. Answers (1)
- As you know, when an object is passed to a function, a copy of that object is made.Further, when that function returns, the copy's destructor...(Solved)
As you know, when an object is passed to a function, a copy of that object is made.Further, when that function returns, the copy's destructor function is called.Keeping this in mind, what is wrong with the following program?
// This program contains an error.
#include
#include
using namespace std;
class dyna {
int *p;
public:
dyna(int i);
~dyna() { free(p); cout << "freeing \n"; }
int get() { return *p; }
};
dyna::dy*) malloc(sizeof(int));
if(!p) {
cout << "Allocation failure\";
exit(1);
}
*p = i;
}
// Return negative value of *ob.p
int neg(dyna ob)
{
retur.get();
}
int main()
{
dyna 0(-10);
cout << o.get() << "\n";
cout << neg(o) << "\n";
dyna o2(20);
cout << o2.get () << "\n";
cout << neg (o2)\n";
cout << o.get () << "\n";
cout << neg (o) << "\n";
return 0;
}
Date posted: May 12, 2018. Answers (1)
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If a queue dynamically allocates memory to hold the queue, explain the reason for that occurence and state whether in such a situation it is possible to block one queue from being assigned to another.
Date posted: May 12, 2018. Answers (1)