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What mass of sodium hydroxide would be needed to neutralize exactly 200 cubic centimetre of a solution containing 49 grammes of sulphuric acid in dm-3

      

What mass of sodium hydroxide would be neededto neutralize exactly 200 cubic centimetre of a solution containing 49 grammes of sulphuric acid in dm^-3

  

Answers


Masinde

2NaOH + H2SO4 = Na2SO4 + 2H2O

moles of H2SO4 in dm3 = Mass of H2SO4 /RFM of H2SO4
mass of H2SO4 = 49
RFM of H2SO4 = 98
Moles =49/98
=0.5 moles
Moles of H2SO4 in 200 cm3 = (0.5 x 200)/1000
=0.1 moles

From the chemical equation above, 2mole of NaOH neutralizes 1moles of H2SO4.

Therefore, moles of NaOH that neutralizes 0.1 moles of H2SO4 = (0.1 x 2)/1
=0.2 moles


Mr Masinde answered the question on June 21, 2018 at 15:00


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