ABCD is a rhombus whose diagonals BD and AC intersect at O. If BD = 10 cm and AC = 6 cm

ABCD is a rhombus whose diagonals BD and AC intersect at O. If BD = 10 cm and AC = 6 cm, find the angles of the rhombus.

Answers

$tan \ \theta = \frac{5}{3} \ = 1.667$

$\theta \ = 59.0367$

$tan \ \alpha = \frac{3}{5} \ = 0.6$

$\alpha \ = 30.9638$

$\angle BCD = 59.0367 \times 2 \ = 118.073^o$

$\angle BAD = \angle BCD = 118.073^o$

$\angle ABC \ = 30.9638 \times 2 \ = 61.928^o$

$\angle ADC \ = \angle ABC \ = 61.928^o$

raphael answered the question on January 20, 2017 at 05:52

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