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Figure 15 shows a battery of e.m.f. 3.0 V connected in series with two capacitors.

      

Figure 15 shows a battery of e.m.f. 3.0 V connected in series with two capacitors.
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Determine the charge stored in the combined capacitors when the switch S is closed.

  

Answers


John
Total capacitance = $\frac{3 \times 3}{3 + 3}$ = 1.5

= 1.5 x 10-6F

Q = CV = 1.5 x 10-6 x 3 = 4.5 x 10-6C
johnmulu answered the question on May 26, 2017 at 12:38


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