Figure 11 shows part of the circuit containing two capacitors of 2uF and 3uF respectively

      

Figure 11 shows part of the circuit containing two capacitors of 2uF and 3uF respectively
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Determine the p.d across AB given that the total charge in the capacitors is 1 x 10-4 coulombs.

  

Answers


John
$C_T\;=C_1+C_2$ = 5 coulombs

V = $\frac{Q}{C}$ = $\frac{1\times 10^{-4}}{5 \times 10^{-6}}$ = 20 V
johnmulu answered the question on May 26, 2017 at 12:55


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