Solve the simultaneous equation
xy=160
Log x- 3log y=1
Ans
Log x- 3log y=1~ log(x /y^3)=1
Hence, x/y^3=10
x=10y^3
Substituting x in equation 1, we have
10 y^3 ×y=160
10y^4=160
y^4=16=2^4
y=2
But, x=10y^3=10(2)^3
Hence x=80
y=2
x=80
Aeren answered the question on July 3, 2018 at 06:59
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