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The tube is now held in a vertical position with the open end facing upwards as shown in figure 8.

      

The tube is now held in a vertical position with the open end facing upwards as shown in figure 8.
physics52920171042.jpg
Determine:
(i) The pressure of the enclosed air.
(ii) The length (l) of the enclosed air column.

  

Answers


John
(i) Atmospheric pressure + pressure due to mercury = 76 + 24 = 100 cmHg

(ii) $P_1V_1 = P_2V_2$ = V2 = $\frac{76 \times 15}{100}$ = 11.4 cm
johnmulu answered the question on May 29, 2017 at 07:51


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