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Figure 7 represents a block of uniform cross sectional area of 6.0 cm2 floating on two liquids A and B. The lengths of the block in each liquid are as shown.

      

Figure 7 represents a block of uniform cross sectional area of 6.0 cm2 floating on two liquids A and B. The lengths of the block in each liquid are as shown.
physics622017313.jpg
Give that the density of liquid A is 800 kgm-3 and that of liquid B is 1000 kgm-3, determine the:
(i) Weight of liquid A displaced
(ii) Weight of liquid B displaced.

  

Answers


John
(i) Velocity of A displaced = 6.0 x 12 cm3

Mass of A displaced = density x volume = 12 x 10-6 x 800 = 0.0096 kg

Weight of A displaced = mass x gravity = 0.0096 x 10 = 0.096 N

(ii) Volume of B displaced = 6.0 x 3 = 18 cm3

Weight of B displaced = v x density x gravity

= 18 x 10-6 x 1000 x 10 = 0.18 N
johnmulu answered the question on June 2, 2017 at 12:20


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