Figure 10 shows a rectangular metal block of density 10500 kgm-3

      

Figure 10 shows a rectangular metal block of density 10500 kgm-3 and dimensions 30 cm x 20 cm x 20 cm suspended inside a liquid of density 1200 kgm-3 by a string attached to a point above the liquid. The three forces acting on the block are the tension T, On the string, the weight W, of the block and the upthrust, U due to the liquid.
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(i) Write the expression relating T, W and U when the block is in equilibrium inside the liquid.
(ii) Determine the weight, W of the block.
(iii) Determine the weight of the liquid displaced by the fully submerged block.
(iv) Hence determine the tension, T in the string.

  

Answers


John
(i) W = T + U

(ii) Volume (V) = 0.3 x 0.2 x 0.2 = 0.012 m3

Weight = mg = 10500 x 0.012 x 10 = 1260

(iii) Volume of liquid = Volume of block

Weight of liquid displaced = Volume x density x gravity = 0.3 x 0.2 x 0.2 x 1200 x 10 = 144 N

(iv) T = W - U = 1260 - 144 = 1116 N


johnmulu answered the question on June 5, 2017 at 06:40


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