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Figure 13 shows a log of wood of mass 20 kg submerged in water in a pond and held in position by a string fixed to the bottom of the pond.

      

Figure 13 shows a log of wood of mass 20 kg submerged in water in a pond and held in position by a string fixed to the bottom of the pond.
physics6520171050.jpg
Given that the density of water is 1000 kgm -3 and that of wood is 800 kgm -3, determine the;
(i) volume of the log
(ii) Upthrust of the log
(iii) Tension in the string.

  

Answers


John
(i) Volume = $\frac{mass}{density}$ = $\frac{20}{800}$ = 0.025 m3

(ii) Volume of water = volume of log = 0.025 m3

Upthrust = 0.025 x 1000 x 10 = 250 N

(iii) Tension + weight = upthrust Tension = 250 - 200 = 50
johnmulu answered the question on June 5, 2017 at 08:28


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