Figure 11 shows a test-tube whose cross-sectional area is 2 cm2 partially filled with lead shot floating vertically in water.

      

Figure 11 shows a test-tube whose cross-sectional area is 2 cm2 partially filled with lead shot floating vertically in water.
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(i) Determine the: volume of the water displaced;
(ii) Determine weight of water displaced.
(iii) State the combined weight of the test-tube and the lead shot.

  

Answers


John
(i) V = cross-sectional area x height

= 2 cm2 x 5 cm = 10 cm3

(ii) Weight = pressure x density x gravity

1000 kg/m3 x 10 x 10 -6m3 x 10

(iii) It is the weight of water displaced = 0
johnmulu answered the question on June 5, 2017 at 08:45


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