In figure 18 ultra-violet (u.v.) light falls on a zinc plate placed on a charged leaf electroscope. It is observed that the leaf collapses.

      

In figure 18 ultra-violet (u.v.) light falls on a zinc plate placed on a charged leaf electroscope. It is observed that the leaf collapses.
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Explain how this observation may be used to determine the type of charge on the electroscope.

  

Answers


John
U.V removes electrons from zinc surface. Since the leaf collapses, the electroscope must be negatively charged. This is because the removed electrons are repelled away by the negative charge on the electroscope thereby discharging the electroscope.
johnmulu answered the question on June 6, 2017 at 06:42


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