$x\;+\;2\;=\; \frac{5x\;+\;1}{4}\;-\frac{1}{2}(x\;+\;1)$
$x\;+\;2$ = $\frac{1(5x\;+\;1)\;-2(x\;+\;1)}{4}$
$x\;+\;2$ = $\frac{5x\;+\;1\;-\;2x\;-2}{4}$
4x + 8 = 3x - 1
combine the like terms
4x - 3x = -1 - 8;
x = -9
johnmulu answered the question on June 7, 2017 at 11:51
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