The perpendicular bisector of AB passes through the midpoint of the line AB.
The midpoint of a line is gotten by, (x1+x2)/2,(y1+y2)/2
=(4+8)/2,(2+2)/2
=(6,2)
The product of the gradients of two perpendicular lines is equal to -1
The gradient of a line is gotten by;
(y2-y1)/(x2-x1)
=(2-2)/(8-4)
=0/4
Let the gradient of the perpendicular bisector= m
m*0/4=-1
m=-4/0
The equation of the perpendicular bisector=
-4/0=(y-2)/(x-6)
-4(x-6)=0(y-2)
-4x+24=0
-4x=-24
x=6
elkyodhiambo50 answered the question on August 30, 2018 at 23:12
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