Solve the equation

Solve the equation
$\frac{3x}{2}$ - $\frac{x\;-\;1}{3}$ = $\frac{1}{2}(3x\;-\;2)$

Answers

$\frac{3x}{2}$ -

$\frac{x\;-\;1}{3}$ =

$\frac{1}{2}(3x\;-\;2)$

$\frac{3x}{2}$ -

$\frac{x\;-\;1}{3}$ =

$\frac{3x}{2}$ - 1

$\frac{3x}{2}$ -

$\frac{x-1}{3}$ -

$\frac{3x}{2}$ = 1

x - 1 = 3;

$\frac{x - 1}{3}$ = 1

x - 1 = 3;

x = 4

johnmulu answered the question on June 7, 2017 at 13:09

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