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$\frac{3x}{2}$ - $\frac{x\;-\;1}{3}$ = $\frac{1}{2}(3x\;-\;2)$
$\frac{3x}{2}$ - $\frac{x\;-\;1}{3}$ = $\frac{3x}{2}$ - 1
$\frac{3x}{2}$ - $\frac{x-1}{3}$ - $\frac{3x}{2}$ = 1
x - 1 = 3; $\frac{x - 1}{3}$ = 1
x - 1 = 3;
x = 4
johnmulu answered the question on June 7, 2017 at 13:09
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