Simplify $\frac{x\;-\;1}{x}$ - $\frac{2x\;+1\;}{3x}$ Hence solve $\frac{x\;-\;1}{x}$ - $\frac{2x\;+\;1}{3x}$ = $\frac{2}{3}$

Simplify $\frac{x\;-\;1}{x}$ - $\frac{2x\;+1\;}{3x}$ Hence solve $\frac{x\;-\;1}{x}$ - $\frac{2x\;+\;1}{3x}$ = $\frac{2}{3}$

Answers

$\frac{x-1}{x}$-$\frac{2x+1}{3x}$

L.C.M of x and 3x is 3x.

$\frac{3(x-1)-1(2x+1)}{3x}$

$\frac{3x-3-2x-1}{3x}$ = $\frac{x-4}{3x}$

$\frac{x-4}{3x}$ = $\frac{2}{3}$, 3x - 12 = 6x

3x = - 12,

x = -4

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johnmulu answered the question on June 7, 2017 at 13:47

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