Point of intersection of the lines.
$\frac{x}{y+1}$ = $\frac{3}{5}$
5x = 3y + 3
5x - 3y = 3 ......................(i)
and
$\frac{x+1}{5}$ = $\frac{y}{2}$
2x + 2 = 5y
2x - 5y = -2 ..................(ii)
Multiply eqn (i) by 2 and eqn(ii) by 5
10x - 6y = 6
10x - 25y = -10
19y = 16
y = $\frac{16}{19}$
Substitute y = $\frac{16}{19}$ in eqn (ii)
2x + 2 = 5($\frac{16}{19}$), 2x + 2 = $\frac{80}{19}$;
2x = $\frac{80-38}{19}$ = $\frac{42}{19}$
38x = 42,
x = $\frac{21}{19}$
The two lines intersect at
($\frac{21}{19},\frac{16}{19}$) or (21,16)
johnmulu answered the question on June 8, 2017 at 08:04
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