If y = 7 - 4x and
y = 3 - $x^2$ then
7 - 4x = 3 - $x^2$
$x^2$ - 4x + 4 = 0
P = 4;
S = -4;
N = -2-2
($x^2-2$) +(-2+ 4) = 0
x(x-2)-2(x-2) = 0
(x-2)(x-2) = 0
x - 2 = 0
x = 2
y = 3 - 4;
Their point of intersection is
(2,-1)
johnmulu answered the question on June 8, 2017 at 08:18
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