Let the cost of a beaker be x and
a testube be y
2x + 5y = 490 .... (i)
3x + 4y = 560 ..... (ii)
Multiply eqn (i) by 2 and eqn (ii) by 3
6x + 15y = 1 470
-6x + 8y = 1 120 - taken away
7y = 350
y = sh 50
Using 2x + 5y = 490;
2x + 250 = 490;
2x = 240
x = sh 120
The cost of 1 beaker is sh 120
and 1 testtube is sh 50
johnmulu answered the question on June 8, 2017 at 09:48
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