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Suppose an oil drop has a volume of 0.10 mm3 and forms a film with a radius of 10 cm. Calculate, the thickness of the...

      

Suppose an oil drop has a volume of 0.10 mm3 and forms a film with a radius of 10 cm. Calculate, the thickness of the oil film.

  

Answers


Mutiso
Area of the film = ${\pi}r^2$ = 3.14 × 10 × 10 = 314 cm2 = 31,400 mm2
Thickness of the oil film = volume / area, hence 0.10 / 31,400 = 3.0 × 10-6 mm. (The
thickness of the oil film is called upper limit to the size of molecule because the molecule
cannot be bigger than the thickness of the oil film).
Mutiso answered the question on October 11, 2018 at 18:41


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