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a) Let the weight of the rod be ‘W’. W acts at 50 cm mark, therefore taking moments about point of suspension, clockwise moments = W × 0.2 Nm = 0.2W Nm.
Anticlockwise moments = 1.6 × 0.3 = 0.48 Nm.
Using the law of moments, then Anticlockwise moments = clockwise moments
0.48 = 0.2 W,
hence W = 2.4 N
b) Upward forces = downward forces
Downward force = W + 1.6 N
= 2.4 + 1.6 = 4.0 N
Upward force = reading of the spring balance = 4.0 N
Mutiso answered the question on October 12, 2018 at 05:28
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