A current of 0.6 A is passed through a step up transformer with a primary coil of 200 turns and a current of 0.1 A...

      

A current of 0.6 A is passed through a step up transformer with a primary coil of 200 turns and a current of 0.1 A is obtained in the secondary coil. Determine the number of turns in the secondary coil and the voltage across if the primary coil is connected to a 240 V mains.

  

Answers

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Np / Ns = Vp / Vs = Ip / Is = Ns = (0.6 × 200) / 0.1 = 1200 turns
Vp = 240 V hence Vs = (240 × 1200) / 200 = 1440 V

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Mutiso answered the question on October 16, 2018 at 11:04

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