An electric kettle is rated at 2,500 W and uses a voltage of 240 V. (a) If electricity costs Ksh 1.10 per kWh, what is...

      

An electric kettle is rated at 2,500 W and uses a voltage of 240 V. (a) If electricity costs Ksh 1.10 per kWh, what is the cost of running it for 6 hrs? (b) What would be its rate of dissipating energy if the mains voltage was dropped to 120 V?

  

Answers


Mutiso
a) Energy transformed in 6 hrs = 2.5 × 6 = 15 kWh. Cost = 15 × 1.10 × 6 = Ksh 99.00
b) Power = V2 / R = 2500. R = (240 × 240) /2500 = 23.04 ${\Omega}$.
Current = V / R = (240 × 2500) / (240 × 240) = 10.42 A
Power = V I = (2500 × 120) / 240 = 1,250 W.
Mutiso answered the question on October 16, 2018 at 18:09


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