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The interior angle of a regular polygon exceeds the exterior by 144^o. Find the

The interior angle of a regular polygon exceeds the exterior by 144^o. Find the
(a) number of sides
(b) sum of interior angles

Answers

(a) Let the exterior angle be x.

Interior = x + 144^o

x + x + 144^o = 180^o

2x = 36^o; X = 18

Number of sides is

$\frac{360}{18}$ = 20 sides

(b) Sum of interior angle is

(2n - 4)90 = (2 x 20 - 4)90

= (40 - 4)90 = 36 x 90

3 240

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johnmulu answered the question on June 12, 2017 at 06:30

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