At equilibrium,
Sum of clockwise = Sum of anti-clockwise
moments moments
( 2.4 x 0.4) = (F x 0.2) + (2.4 x 0.1) since moments at 30 cm mark acts upward
0.96 = 0.2F + 0.24
0.2F = 0.96 - 0.24
0.2F = 0.72
F = 0.72/0.2
=3.6N
M = F x d
=3.6 x 0.2
=0.72 Nm
Nchoga answered the question on November 18, 2018 at 07:16
- Explain the applications of junction diodes(Solved)
Explain the applications of junction diodes.
Date posted: October 18, 2018. Answers (1)
- Explain the occurrence of forward bias of a p-n junction and reverse bias of a p-n junction(Solved)
Explain the occurrence of forward bias of a p-n junction and reverse bias of a p-n junction.
Date posted: October 18, 2018. Answers (1)
- What are junction diodes?(Solved)
What are junction diodes?
Date posted: October 18, 2018. Answers (1)
- What is an intrinsic semiconductor?(Solved)
What is an intrinsic semiconductor?
Date posted: October 18, 2018. Answers (1)
- Define the following terms (i) Conductors (ii) Insulators (iii) Semiconductors (Solved)
Define the following terms (i) Conductors (ii) Insulators (iii) Semiconductors
Date posted: October 18, 2018. Answers (1)
- Hazards of radioactivity and their precautions(Solved)
Hazards of radioactivity and their precautions
Date posted: October 17, 2018. Answers (1)
- A radioactive element has an initial count rate of 2,400 counts per minute on a scaler. The count rate falls to 300 units per minute...(Solved)
A radioactive element has an initial count rate of 2,400 counts per minute on a scaler. The count rate falls to 300 units per minute in 30 hours, (a) Calculate the half-life of the element (b) If the initial number of atoms in another sample of the same element is 6.0 × 1020, how many atoms will have decayed in 50 hours?
Date posted: October 17, 2018. Answers (1)
- The initial number of atoms in a sample is 5.12 × 1020. If the half-life of the sample is 3.0 seconds, determine the number of...(Solved)
The initial number of atoms in a sample is 5.12 × 1020. If the half-life of the sample is 3.0 seconds, determine the number of atoms that will have decayed after six seconds.
Date posted: October 17, 2018. Answers (1)
- An isotope has a half-life of 576 hours. Complete the following table and show how mass varies with time from an initial mass of 1280...(Solved)
An isotope has a half-life of 576 hours. Complete the following table and show how mass varies with time from an initial mass of 1280 g?
Time (hrs)----576--1152--1728---2304
Mass (g)-------640--x------y-----z
Date posted: October 17, 2018. Answers (1)
- The half-life of a sample of a radioactive substance is 98 minutes. How long does it take for the activity of the sample to reduce...(Solved)
The half-life of a sample of a radioactive substance is 98 minutes. How long does it take for the activity of the sample to reduce to 1/16th of the original value?
Date posted: October 17, 2018. Answers (1)
- State the law of radioactive decay(Solved)
State the law of radioactive decay
Date posted: October 17, 2018. Answers (1)
- Explain ways of detecting nuclear radiation(Solved)
Explain ways of detecting nuclear radiation.
Date posted: October 17, 2018. Answers (1)
- Properties of radioactive emissions(Solved)
Properties of radioactive emissions
Date posted: October 17, 2018. Answers (1)
- Sodium has a work function of 2.0 e: Calculate (a) The maximum energy and velocity of the emitted electrons when sodium is Illuminated by...(Solved)
Sodium has a work function of 2.0 e: Calculate
(a) The maximum energy and velocity of the emitted electrons when sodium is Illuminated by a radiation of wavelength 150 nm.
(b) Determine the least frequency of radiation by which electrons are emitted. (Take ‘h’ = 6.626 × 10-34 Js, e = 1.6 × 10-19, c = 3.0 × 108 m/s and mass of electron = 9.1 × 10-31 kg).
Date posted: October 17, 2018. Answers (1)
- The threshold frequency for lithium is 5.5 × 1014 Hz. Calculate the work function for lithium. (Take ‘h’ = 6.626 × 10-34 Js)(Solved)
The threshold frequency for lithium is 5.5 × 1014 Hz. Calculate the work function for lithium. (Take ‘h’ = 6.626 × 10-34 Js)
Date posted: October 17, 2018. Answers (1)
- The work function of tungsten is 4.52 e V. Find the cut-off potential for photoelectrons when a tungsten surface is illuminated with radiation of wavelength...(Solved)
The work function of tungsten is 4.52 e V. Find the cut-off potential for photoelectrons when a tungsten surface is illuminated with radiation of wavelength 2.50 × 10-7 m. (Planck’s constant, h = 6.62 × 10-34 Js).
Date posted: October 17, 2018. Answers (1)
- The cut-off wavelength for a certain material is 3.310 × 10-7 m. What is the cut-off frequency for the material?(Solved)
The cut-off wavelength for a certain material is 3.310 × 10-7 m. What is the cut-off frequency for the material?
Date posted: October 17, 2018. Answers (1)
- What is Einstein’s photoelectric equation?(Solved)
What is Einstein’s photoelectric equation?
Date posted: October 17, 2018. Answers (1)
- Dangers of X-rays and the precautions(Solved)
Dangers of X-rays and the precautions.
Date posted: October 16, 2018. Answers (1)
- An x-ray tube operates at 60 kV and the current through it is 4.0 mA. Calculate the, (a) Number of electrons striking the target per...(Solved)
An x-ray tube operates at 60 kV and the current through it is 4.0 mA. Calculate the, (a) Number of electrons striking the target per second. (b) Speed of the electrons when they hit the target.
Date posted: October 16, 2018. Answers (1)