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$3^{2(x-\frac{1}{2})}$ = $3^{3(\frac{3}{4}x-5)}$
2x - 1 = $\frac{9}{4}x - 15$
-1 + 15 = 2$\frac{1}{4}$x - 2x
14 = $\frac{1}{4}x$;
x = 56
johnmulu answered the question on June 12, 2017 at 08:02
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