Solve for x

Solve for x in $9^{x-\frac{1}{2}}$ = $27^{\frac{3}{4}x -5}$

Answers

$3^{2(x-\frac{1}{2})}$ = $3^{3(\frac{3}{4}x-5)}$

2x - 1 = $\frac{9}{4}x - 15$

-1 + 15 = 2$\frac{1}{4}$x - 2x

14 = $\frac{1}{4}x$;

x = 56

johnmulu answered the question on June 12, 2017 at 08:02

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