Solve for x in 4^x + 2^2x+1 = 24

      

Solve for x in 4^x + 2^2x+1 = 24

  

Answers

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4^x + 2^2x+1 = 24

2^2x + 2^2x+1 = 24

2^2x + 2^2x 2¹ = 24

let 2^2x = y

y + 2y = 24

3y = 24;

y = 8,

but y = 2^2x

2^2x = 8,

2^2x = 2³

2x = 3;

x = $\frac{3}{2}$ = 1$\frac{1}{2}$

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johnmulu answered the question on June 12, 2017 at 13:49

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