Solve for x in 125^x+1 + 5^3x = 630

      

Solve for x in 125^x+1 + 5^3x = 630

  

Answers

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125^x-1 + 5^3x = 630

5^3(x-1) + 5 = 630;

5^3x-3 + 5 = 630

$\frac{5^{3x}}{5^3}$ + $5^{3x}$ = 630,

Let 5^3x = a

$\frac{a}{125}$ + a = 630

a + 125a = 78 750

126a = 78 750

a = 625

5^3x = 5⁴

x = $\frac{4}{3}$

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johnmulu answered the question on June 13, 2017 at 05:20

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