Length of a line
= √(x1−x2)2+(y1−y2)
= 25 = (3 -7)2 + (y - 5)2
= 25 = 16 + y2 - 10y + 25
y2 - 10y + 16 = 0
P = 16
S = -10 N = -8 -2
(y2 -8y) -(2y + 16) = 0
y(y - 8) -(2y + 16) = 0
(y - 2)(y - 8) = 0
y = 2 or y = 8
johnmulu answered the question on June 13, 2017 at 07:48
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