Find the equation of a line whose gradient is -$\frac{2}{3}$ and passes through point (-2,3)

Answers

Equation is

$\frac{y-3}{x+2}$ = $\frac{-2}{3}$;

3y - 9 = -2x - 4;

3y = -2x - 4 + 9;

3y = -2x + 5;

3y + 2x - 5 = 0

johnmulu answered the question on June 13, 2017 at 08:35

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