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Gradient of the line
2y = 3x + 5;
y = $\frac{3}{2}x+ \frac{5}{2}$
$m_1$ = gradient = $\frac{3}{2}$
For perpendicular lines
$m_1m_2=-1$ $m_2 = - \frac{2}{3}$
The equation of the line
through (2,-1) is $\frac{y+1}{x-2}$ = - $\frac{2}{3}$
3y + 3 = -2x + 4; 3y = -2x + 4 - 3
3y = -2x + 1;
2x + 3y - 1 = 0
johnmulu answered the question on June 13, 2017 at 09:12
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